Which statement distinguishes a three-phase fault from a single-line-to-ground fault in terms of current path?

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Multiple Choice

Which statement distinguishes a three-phase fault from a single-line-to-ground fault in terms of current path?

Explanation:
Current path in faults depends on how many conductors are involved. In a three-phase fault, the fault connects the three phase conductors with each other, so current flows in all three lines. The fault current is distributed among the three phases, often in a balanced way for a symmetrical fault, and the return path isn’t limited to ground. In a single-line-to-ground fault, currents flow from the one faulted phase down to the earth and back to the source through the grounding system, so only that one phase carries the fault current with a clear ground path. So the correct distinction is that a three-phase fault involves all three phases, while a single-line-to-ground fault involves one phase and ground.

Current path in faults depends on how many conductors are involved. In a three-phase fault, the fault connects the three phase conductors with each other, so current flows in all three lines. The fault current is distributed among the three phases, often in a balanced way for a symmetrical fault, and the return path isn’t limited to ground. In a single-line-to-ground fault, currents flow from the one faulted phase down to the earth and back to the source through the grounding system, so only that one phase carries the fault current with a clear ground path.

So the correct distinction is that a three-phase fault involves all three phases, while a single-line-to-ground fault involves one phase and ground.

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